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Experiment
6
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Percent
Composition of a Carbonate
Overview
"Carbonates" are compounds which contain the carbonate ion, CO32-.
In this experiment you will be given a sample of an "unknown"
carbonate, and you will determine what percentage (by mass) of
carbonate ion the compound contains. Although you will make three
determinations of your sample, realize that the percent
carbonate calculated for your sample should be the same
(within reasonable experimental error) for each of the
determinations. If you are not careful in this experiment, or if you
hurry the experiment because it seems so "easy" to perform, you will
receive poor agreement between your three determinations and you
will receive a poor grade on your lab report.
When a compound containing the carbonate ion is treated with an
acid, the following net reaction occurs
2H+(aq) + CO32-
(aq) ® H2O(l)
+ CO2(g)
CO2 is a gas and is lost from the carbonate
sample when the acid is added to the sample. In this experiment, we
determine how much carbonate ion is present in a sample by measuring
the loss in mass (which represents the CO2 that
escapes) when acid is added to the sample. For example, if a
carbonate sample decreases in mass by 0.2571 g when treated with
acid, then the sample must have contained the following amount of
carbonate ion:
The numbers (60.01 g CO32-/mol) and (44.01
g CO2/mol) are the molar masses (formula weights) of the
carbonate ion and carbon dioxide, respectively.
You perform this experiment in "microscale" using very small
samples. For this purpose, balances are provided which make mass
determinations to 0.0001 g (four decimal places). You
should carry out all your calculations maintaining this level of
precision.
Calculations
Suppose the following data have been recorded for the analysis of
a carbonate sample (Page 27, Part I)
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Trial 1
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Trial 2
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Trial 3
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Mass beaker, tube, HCl
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9.7821 g |
9.8835 g
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9.6642 g |
Mass beaker, tube, HCl, sample (before rxn)
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10.2758 g |
10.3792 g
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10.1667 g |
Mass beaker, tube, HCl, sample (after rxn)
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10.0536 g |
10.1561 g
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9.9410 g |
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Page 27 Part II
1. Mass of sample (for Trial 1)
The mass of carbonate sample added to the test tube for Trial 1
will be the difference in mass between the (mass of beaker, tube,
HCl, sample before reaction) and the (mass of beaker, tube HCl).
Using the data above, calculate the mass of carbonate sample for
Trial 1, then click
here to
check your answer.
2. Mass of CO2 evolved (for Trial 1)
The mass of CO2 evolved represents the change in mass
before and after the reaction (i.e., when the acid was transferred
from the pipet to the carbonate sample). For the table of data
above, the mass of carbon dioxide evolved represents the difference
between the (mass of beaker, tube, HCl, sample before reaction) and
the (mass of beaker, tube, HCl, sample after reaction). Calculate
the mass of CO2 evolved for Trial 1 above, then click
here to
check your answer.
3. Percent Carbonate in Unknown (for Trial 1)
The actual mass of carbonate in the sample used for Trial
1 must first be calculated, before the percent carbonate can
be determined. The sample for Trial 1 evolved 0.2222 g CO2.
The mass of carbonate ion that would enable this amount of CO2
to be generated is
The numbers (60.01 g CO32-/mol) and (44.01
g CO2/mol) are the molar masses (formula weights) of the
carbonate ion and carbon dioxide, respectively.
The percent carbonate in the sample used in Trial 1 is based on
the mass of carbonate ion in the sample (0.3030 g CO32-)
and the total mass of the sample before reaction (0.4937 g).
Calculate the percent carbonate determined for the sample used in
Trial 1 above, then click
here to
check your answer.
4. Average % carbonate in unknown
This represents the sum of the % carbonates determined for the
three trials, divided by the number of trials (three). The three
individual percentages determined for the three Trials are shown
below, along with the calculation of the average percent carboonate.
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Trial 1
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Trial 2
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Trial 3
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% Carbonate
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61.37% CO32-
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61.37% CO32-
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61.24% CO32-
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5. Deviations in % Carbonate
For Trial 1, the deviation from the average is calculated as
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Deviation Trial 1 = (61.37% - 61.33%) = 0.04% CO32-
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Trial 1
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Trial 2
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Trial 3
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Deviation
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0.04 % CO32-
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0.04 % CO32-
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-0.09 % CO32-
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6. Average Deviation in % Carbonate
The average deviation is the sum of the absolute values of the
individual deviations, divided by the number of trials (three)
7. Summary of results
For the sample data above, we would report the % carbonate in the
unknown sample as
Question
This problem is solved almost exactly the same way you treat the
data in your experiment. The data is given in a slightly different
format, however, so make sure you know what number to use in what
place. The answer is 17.13% carbonate but you will have to show
exactly how to get this answer to receive credit for the problem on
your lab report.
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