We took 50.0 mL of 0.950 M NaOH and combined it with 50.0 mL of 0.981 M HCl. The reactant which is present in the lesser amount on a mole/stoichiometric basis is the limiting reactant. For our experiment, the NaOH is the limiting reactant. Some of the HCl is present in excess and does not react. The number of moles of NaOH present is

(50.0 mL)(1 L/1000 mL)(0.950 mole/L) = 0.0475 moles NaOH