a b c ad = bc + 1 dor (rotated)
a b
ad = bc + 1
c d
I decided to look at the "square" initial conditions: x_ij is given
for i = 0 or j = 0. I wrote Mathematica code (nb, txt) to solve this
recurrence and represent the monomials in an easy-to-read format; here
is some output. From this output it was
easy to conjecture a general form for the solution:
x_i0 * x_0j i 1 j 1
x_ij = ----------- + (sum -------------) (sum -------------).
x_00 k=1 x_k0 x_(k-1)0 k=1 x_0k x_0(k-1)
Reading the
antifrieze
notes revealed the combinatorial origin of this formula: the monomials
correspond to paths through the graph
+---+---+ +---+ |x00|x01|...|x0j| +---+---+ +---+ |x10| +---+ . . +---+ |xi0| +---+from the lower-left vertex to the upper-right vertex; the exponent of each variable is related to the number of edges in the path which touch it.
The combinatorial interpretation of these frieze patterns seems to be
fairly well understood, so I decided to look at other two-dimensional
recurrences.
2. Number walls
To be continued...